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The SolvEnergy command calculates the interaction energy between the solvent and the solute. This is done by treating the solvent as a continuum without explicit solvent molecules.
The 'solute' consists of all the atoms in the simulation cell and thus includes all water molecules that are present. The usual approach is therefore to delete all explicit solvent molecules before running the
SolvEnergy command. Results are returned in units of either kJ/mol or kcal/mol, depending on the current
EnergyUnit. The
Method parameter will allow to choose among methods with different accuracy/performance trade-offs in the future. Currently only a very fast first-order boundary element approximation to the solvation energy is supported.
BoundaryFast: This method performs the following steps:
TotalInducedCharge = SumOverSoluteCharges*(eSolute-eSolvent)/(eSolute+eSolvent)
where eSolute and eSolvent are the dielectric constants passed to the
SolvEnergy command.
As a side-effect, the command calculates the molecular surface area which is returned as the second value. This surface area can then be used to estimate the non-electrostatic components of the solvation energy: the Van der Waals interaction energy between solvent and solute,
and (for free energy calculations) the energy of cavity formation. Note that the solvent accessible surface area is often better suited for these calculations,
e.g. a common empirical formula (from 'Computational Medicinal Chemistry for Drug Discovery',
page 271) is: NonElectrostaticSolvEnergy [kcal/mol]
= 0.85 + 0.005 * SolventAccessibleSurfaceArea [A^2, probe radius 1.4 A]
Since the 'BoundaryFast' method has been calibrated to reproduce solvation energies obtained with slower methods,
it critically depends on (and thus enforces) certain surface parameters
(e.g. numeric molecular surface, probe radius 1.4 A, solvation radii). Example 1:SolvEnergy Calculate the solvation energy for the atoms in the cell using a dielectric constant of
1 for the solute and 80 for the solvent. Example 2:energy,surfarea = SolvEnergy As above, and assign the result to variable 'energy'. In addition,
the molecular surface area is assigned to 'surfarea'. Example 3:SolvEnergy eSolute=4,eSolvent=50 Calculate the solvation energy for a solute with dielectric constant
4 in a solvent with dielectric constant 50. | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||